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Marginal probability

Marginal probability adds joint probabilities over the other outcomes. Read a return-direction table, separate marginals from conditionals, and see what co-movement information is lost.

Marginal probability is the probability of an event with the outcomes of other variables left unrestricted. In a joint return model, “asset A rises” is a marginal question: asset B may rise or fall. “Both assets rise” asks for a joint probability.

This is useful when a desk moves from a multi-asset scenario model to a single-name report. The report can retain each asset's chance of a loss while discarding information about whether their losses occur together. That discarded information matters for portfolio risk.

Add every way the event can happen

Suppose a hypothetical model classifies the returns of two assets over the same fixed period as up or down. The model excludes flat returns; these two categories are exhaustive for each asset. Its joint probabilities are:
A's directionB upB downA marginal
A up0.420.180.60
A down0.080.320.40
B marginal0.500.501.00

The four interior cells sum to one. A rises in two mutually exclusive cases: B rises too, or B falls. Therefore,

P(A up)=0.42+0.18=0.60.\mathbb{P}(A\text{ up})=0.42+0.18=0.60.

Likewise, P(B up)=0.42+0.08=0.50\mathbb{P}(B\text{ up})=0.42+0.08=0.50. These are model probabilities, not measurements from market data. A larger chance of an up move also does not establish a larger expected return: the magnitudes of gains and losses are absent from this direction-only model.

Joint direction table with cells 0.42, 0.18, 0.08 and 0.32. Horizontal arrows add to A marginals 0.60 and 0.40; vertical arrows add to B marginals 0.50 and 0.50.
Joint direction table with cells 0.42, 0.18, 0.08 and 0.32. Horizontal arrows add to A marginals 0.60 and 0.40; vertical arrows add to B marginals 0.50 and 0.50.
Read the margins by adding over the other asset's two directions. Original synthetic one-period model; all entries are probabilities.
More generally, if B1,…,BnB_1,\ldots,B_n form a disjoint, exhaustive partition of the sample space, then
P(A)=∑j=1nP(A∩Bj).\mathbb{P}(A)=\sum_{j=1}^{n}\mathbb{P}(A\cap B_j).
Each outcome in A belongs to exactly one partition piece, so it is counted once. Overlapping pieces would double-count some outcomes; incomplete pieces could omit probability. Countable partitions use the corresponding infinite sum. For discrete random variables, the same operation gives P(X=x)=∑yP(X=x,Y=y)\mathbb{P}(X=x)=\sum_y\mathbb{P}(X=x,Y=y); repeating it for every value of X produces its marginal distribution. With a joint density, the analogous operation integrates over the other variable.

Summing out is different from conditioning

A marginal calculation keeps the entire probability space. Conditioning restricts attention to an observed event and rescales its probability mass. In this example,
P(A up∣B up)=0.420.50=0.84.\mathbb{P}(A\text{ up}\mid B\text{ up}) =\frac{0.42}{0.50}=0.84.
The denominator is the probability of B up, which is positive here. Thus 0.60 answers the question before restricting B's direction, while 0.84 answers it within the B-up part of the model. A marginal can already reflect background information used to construct that model; “marginal” does not mean devoid of information.
If a table supplies conditional probabilities instead of joint probabilities, adding its entries directly is generally wrong. Weight each conditional by its conditioning-event probability first. This is the law of total probability, with conditional terms used only for positive-probability partition pieces.

The margin hides co-movement

Marginalisation requires no independence assumption. Indeed, the example is dependent:
P(A up,B up)=0.42≠0.60×0.50=0.30.\mathbb{P}(A\text{ up},B\text{ up})=0.42 \ne 0.60\times0.50=0.30.
An independent model with the same marginals would have interior cells 0.30,0.300.30,0.30 in its first row and 0.20,0.200.20,0.20 in its second. Both models give A an up probability of 0.60 and B an up probability of 0.50. Yet the probability of both falling is 0.32 in the original model and 0.20 in the independent one. Separate probabilities cannot identify simultaneous-loss risk. Keep the joint distribution when the question concerns the portfolio.
For a fuller treatment, Joint Distributions and Dependence develops marginalisation in its “Joint laws and marginals” section, then connects dependence to portfolio variance. The public link provides a preview; the full lesson requires membership.

Sources

  • Dimitri P. Bertsekas and John N. Tsitsiklis, Introduction to Probability, 2nd edition (2008), §2.5, “Joint PMFs of Multiple Random Variables”: marginal PMFs and additivity over the other variable's values.
  • Marco Taboga, “Marginal probability mass function”, Lectures on Probability Theory and Mathematical Statistics (2021): marginal PMFs of components of a discrete random vector.
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  • probability
  • marginalisation
  • joint probability
  • dependence
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