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Transient state

A transient Markov-chain state has a positive chance of never returning. Repeated visits are possible, but their expected total is finite.

A transient state of a time-homogeneous, discrete-time Markov chain is a state that, when started there, has a positive probability of never being visited again after time zero. The chain visits it only finitely many times, almost surely; its expected total number of visits is also finite.

In a regime model, transience can encode a phase the system eventually leaves behind. This matters when using long-run regime weights to assess risk: a state with no long-run weight can still dominate the next few observations. Classification is a statement about the chosen model, not evidence that an observed market regime can never reappear.

Return is allowed

Let the first return time to state ii be

τi+=inf⁡{n≥1:Xn=i},inf⁡∅=∞,\tau_i^+=\inf\{n\ge1:X_n=i\},\qquad \inf\varnothing=\infty,
and write fii=Pi(τi+<∞)f_{ii}=\mathbb{P}_i(\tau_i^+<\infty), where the subscript means X0=iX_0=i. Transience means fii<1f_{ii}<1; a recurrent state has fii=1f_{ii}=1. A self-transition at the next step counts as a return, even if the chain has not left the state.
“Transient” does not mean “visited at most once.” It allows repeated visits, including departures followed by returns. For example, a state may lead to a second state that sometimes sends the chain back and sometimes sends it into a permanent exit. What matters is that continued returns eventually stop with probability one.

A phase that can linger

Suppose a hypothetical model has an initial regime TT and two enduring regimes C1,C2C_1,C_2. One step is one day. In that order, the row transition matrix is
P=(1/21/41/403/41/401/21/2),X0=T.P=\begin{pmatrix} 1/2&1/4&1/4\\ 0&3/4&1/4\\ 0&1/2&1/2 \end{pmatrix},\qquad X_0=T.
The probabilities are stipulated, not fitted to market data. Each day in TT, the model remains there with probability 1/21/2. Otherwise it enters the closed communicating class {C1,C2}\{C_1,C_2\}. Once it leaves TT, there is no route back. That last feature belongs to this example; it is not required for transience in general.

Starting at TT, the only possible first return is tomorrow's self-transition. Hence fTT=1/2f_{TT}=1/2. Yet the chain can remain in TT for any finite number of days with positive probability. There is no predetermined departure date.

The chance of being in TT after nn days is

PT(Xn=T)=(12)n.\mathbb{P}_T(X_n=T)=\left(\frac12\right)^n.

After four days it is 1/16=6.25%1/16=6.25\%. The probability of staying there forever is the limit of these probabilities, zero.

Starting in transient regime T, its day-n probability is 2 to the power minus n: 100% initially, 50% after one day and 6.25% after four. Expected visits including day zero rise from 1 to 1.9375 through day four and approach 2.
Starting in transient regime T, its day-n probability is 2 to the power minus n: 100% initially, 50% after one day and 6.25% after four. Expected visits including day zero rise from 1 to 1.9375 through day four and approach 2.
Exact daily model starting in T. Filled dots mark integer days; joining lines are guides. The left panel is a probability at one time; the right adds expected visits from day 0 through that time.

Counting the visits

For a general transient state, let Vi=∑n=0∞1{Xn=i}V_i=\sum_{n=0}^{\infty}\mathbf{1}_{\{X_n=i\}} count all visits, including the initial one. Each successful return restarts the same return question. Thus
Pi(Vi=k)=(1−fii)fiik−1,k=1,2,…,\mathbb{P}_i(V_i=k)=(1-f_{ii})f_{ii}^{k-1},\qquad k=1,2,\ldots,

and

Ei[Vi]=11−fii=∑n=0∞(Pn)ii<∞.\mathbb{E}_i[V_i] =\frac{1}{1-f_{ii}} =\sum_{n=0}^{\infty}(P^n)_{ii}<\infty.
The expected number of returns, excluding time zero, is instead fii/(1−fii)f_{ii}/(1-f_{ii}). These two counts differ by one. Durrett's §1.3 derives the visit-count criterion; Cambridge's notes, §5 give the equivalent summability and return-probability tests.

In our model, PT(VT=k)=2−k\mathbb{P}_T(V_T=k)=2^{-k} and ET[VT]=2\mathbb{E}_T[V_T]=2. That mean is not a maximum: the probability of at least four visits is 1/81/8. Through day four, the expected accumulated count is already 1+1/2+1/4+1/8+1/16=1.93751+1/2+1/4+1/8+1/16=1.9375. A quickly shrinking current probability and meaningful cumulative exposure can coexist.

The states C1,C2C_1,C_2 are recurrent because they form a finite closed communicating class. Neither is an absorbing state: the model continues moving between them. Its stationary distribution is (0,2/3,1/3)(0,2/3,1/3). The zero weight on TT captures its long-run disappearance, while the initial distribution puts probability one there. A risk calculation for the coming days should retain that initial condition.
For the derivation of the visit-count test and finite-chain stationary calculations, see SelfMadeQuant's Recurrence, Transience, and Stationary Distributions lesson (membership; public preview available).

Sources

  • Richard Durrett, Essentials of Stochastic Processes, third edition, Springer, 2016, §1.3, especially Lemmas 1.11–1.12. Publisher DOI.
  • Richard Weber, Markov Chains, University of Cambridge course notes, October 2011, §§5.1–5.5. Course notes.
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  • markov chains
  • transience
  • return probabilities
  • regime models
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