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Exponential function

An exponential function puts its variable in the exponent. Understand positive bases, equal-step multipliers and constant proportional change through a stipulated cash-balance model.

An exponential function has a fixed positive base and a variable in the exponent:
f(x)=ax,a>0,a≠1.f(x)=a^x,\qquad a>0,\quad a\ne1.

The input xx can be any real number, and the output is always positive. The base restriction matters: a negative base does not give a real-valued function for every real input, while zero fails for negative inputs. The excluded case a=1a=1 produces the constant function 11.

The location of the variable distinguishes the family. In 2x2^x, the base stays fixed while the exponent changes. In x2x^2, the exponent stays fixed while the base changes: that is a power function. Their algebra and differentiation rules differ.

Equal steps, equal multipliers

The defining operational property is

f(x+h)=ax+h=axah=f(x)ah.f(x+h)=a^{x+h}=a^x a^h=f(x)a^h.
A fixed step hh in the input multiplies the output by the same factor aha^h, wherever the step starts. It does not add a fixed amount. When a>1a>1, increasing the input produces exponential growth; when 0<a<10<a<1, it produces exponential decay. Both curves pass through (0,1)(0,1) and remain above zero.

Multiplying by a positive starting value CC gives y(x)=Caxy(x)=Ca^x, a scaled exponential. Its equal-step ratio is still aha^h, but y(0)=Cy(0)=C. Be careful with the identity f(x+h)=f(x)f(h)f(x+h)=f(x)f(h): it applies to the normalised function axa^x. For the scaled version, y(x+h)=y(x)y(h)/Cy(x+h)=y(x)y(h)/C.

A cash balance with an exponential clock

Suppose a hypothetical account starts with USD 1,000, earns a stipulated constant 5% continuously compounded annual rate, and has no deposits, withdrawals, fees or taxes. With tt measured in years, its model balance is
B(t)=1,000e0.05t.B(t)=1{,}000e^{0.05t}.

Here e≈2.71828e\approx2.71828 is the natural base. The normalised accumulation factor f(t)=e0.05tf(t)=e^{0.05t} starts at 11 and satisfies f(t+s)=f(t)f(s)f(t+s)=f(t)f(s). The exponent 0.05t0.05t is dimensionless: an annual rate multiplies a time in years.

TimeModel balanceGain over preceding two years
0 yearsUSD 1,000.00—
2 yearsUSD 1,105.17USD 105.17
4 yearsUSD 1,221.40USD 116.23

Each two-year interval multiplies the balance by e0.1≈1.105171e^{0.1}\approx1.105171. The second dollar gain is larger because the same multiplier acts on a larger starting balance.

A stipulated USD 1,000 account at a constant 5% continuous annual rate reaches USD 1,105.17 after two years and USD 1,221.40 after four. Each two-year multiplier is 1.105171; the gains are USD 105.17 and USD 116.23.
A stipulated USD 1,000 account at a constant 5% continuous annual rate reaches USD 1,105.17 after two years and USD 1,221.40 after four. Each two-year multiplier is 1.105171; the gains are USD 105.17 and USD 116.23.
Original hypothetical model: equal two-year intervals share one multiplier, while their dollar gains differ. Rate and time units are fixed throughout.

This is a specified accumulation rule, not a forecast of an investment's realised returns. A 5% continuous rate also differs from a 5% effective annual rate: the former produces an annual gain of e0.05−1≈5.127%e^{0.05}-1\approx5.127\%. Changing rates or external cash flows require a different balance model.

Why the natural base appears in calculus

Every positive base can be written using a logarithm: ax=exln⁡aa^x=e^{x\ln a}. Differentiating shows that an exponential's rate of change is proportional to its current level:
f′(x)=(ln⁡a)f(x),f′(x)f(x)=ln⁡a.f'(x)=(\ln a)f(x), \qquad \frac{f'(x)}{f(x)}=\ln a.
For the account, B′(t)=0.05B(t)B'(t)=0.05B(t). At two years the instantaneous slope is about USD 55.26 per year. This is a local rate of change; the exact gain over the next year uses the multiplier e0.05e^{0.05}.
The special case exe^x has derivative exe^x. More precisely, it is the unique solution of y′=yy'=y with y(0)=1y(0)=1; without that initial condition, every CexCe^x solves the same differential equation. Constant proportional change, rather than constant dollar change, is the useful pattern to recognise.
For a fuller treatment of exponent laws, logarithmic inverses and rate calculations, see Exponentials and Logarithms (public preview; full lesson requires membership).

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